p^2+2p(0.0667)+(.667)^2=1

Solution for p^2+2p(0.0667)+(.667)^2=1 equation:

p^2+2p(0.0667)+(.667)^2=1

We move all terms to the left:

p^2+2p(0.0667)+(.667)^2-(1)=0

determiningTheFunctionDomain
p^2+2p(0.0667)-1+(.667)^2=0

We add all the numbers together, and all the variables

p^2+2p(0.0667)-1+(0.667)^2=0

We add all the numbers together, and all the variables

p^2+2p(0.0667)-0.555111=0

We multiply parentheses

p^2+0.1334p-0.555111=0

a = 1; b = 0.1334; c = -0.555111;
Δ = b2-4ac
Δ = 0.13342-4·1·(-0.555111)
Δ = 2.23823956
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1334)-\sqrt{2.23823956}}{2*1}=\frac{-0.1334-\sqrt{2.23823956}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1334)+\sqrt{2.23823956}}{2*1}=\frac{-0.1334+\sqrt{2.23823956}}{2}
$